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Mobilesuitgundamseeddestinyrengouvszaftiiisops2 Mobilesuitgundamseeddestinyrengouvszaftiiisops2 Mobilesuitgundamseeddestinyrengouvszaftiiisops2.Q: How to force conversion of strings to pointers or single char in C? For one of my assignments, I need to read a text file. However, while reading, I get a pointer. stringReader* reader; char* textPtr; string textValue; char text[100]; while (!stringReader->at_end) { stringReader->read_next_word(text); strcpy(textPtr, &textValue); textValue = textPtr; } I get the error: [Error] incompatible types when assigning to type ‘char *’ from type ‘char’ textPtr is of type char*, so I’m not sure how to fix this. I can’t just make textPtr a string because if I do that, the assignment statement also fails. A: The issue is that you are trying to assign a pointer to a character array. That’s not allowed in C, as pointers are never arrays. You can, however, assign pointers to character arrays: char text[100] = “”; char *textPtr = text; Or if you want a smaller size, or if you want to reallocate the text dynamically: char text[100] = {}; char *textPtr = text; … Finally, why are you trying to return a pointer when the function returns a string? Q: TypeError: Cannot read property’map’ of undefined I have created a simple project in angular.js, I am getting errors like this. TypeError: Cannot read property’map’ of undefined at Object.update ( 79a2804d6b


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